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Sinopsis
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1922 Excerpt: ...of arc, the black type is considered; each black figure represents that number of minutes, and each of the 4 divisions between each black figure stands for 15". Continuing the problem further, the following example will give approximately the longitudes that Captain Sumner must have had, working the same altitude with three latitudes and the chronometer time, found by applying the longitude, and an equation of time of 03m. 03s.--to mean time. The three examples with the resulting longitudes are doubtless nearly those obtained by Captain Sumner himself. A line drawn at right angles to the sun's true bearing corresponding to the apparent time at ship, runs almost exactly E. N. E. true, and may possibly be as near that point as Captain Sumner was, considering the compass he may have had at that period. The line runs through the three longitude spots and Smalls light as well, as he described it. Latitude 51 43' was first used, as it was known to be the nearest to the ship's place, then 51 33', and last 51 53', all worked with the same chronometer time. The first one plots 15' East of the position by dead reckoning. The longitudes are not quite 27 miles apart as described, but 25 and 25.7, respectively. The latitude by dead reckoning increased 8 miles intersects the line of position 31' East of the longitude which the incorrect latitude would have given. It will now be shown how to find the sun's true bearing to correspond with the examples just given, by an altitude azimuth. The rule follows on the next page. Sun's declination 23 25' 90 00 Sun's polar distance 113 25 True altitude 11 44 Secant =.00917 Latitude by dead reckoning 51 43 Secant =.20792 Divided by 2)176 52 Half sum 88 26 Cosine = 8.43680 Polar distance-113 25 Remainder 24 59 Cosine = 9.95733 Su...
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Reseña del editor
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1922 Excerpt: ...of arc, the black type is considered; each black figure represents that number of minutes, and each of the 4 divisions between each black figure stands for 15". Continuing the problem further, the following example will give approximately the longitudes that Captain Sumner must have had, working the same altitude with three latitudes and the chronometer time, found by applying the longitude, and an equation of time of 03m. 03s.--to mean time. The three examples with the resulting longitudes are doubtless nearly those obtained by Captain Sumner himself. A line drawn at right angles to the sun's true bearing corresponding to the apparent time at ship, runs almost exactly E. N. E. true, and may possibly be as near that point as Captain Sumner was, considering the compass he may have had at that period. The line runs through the three longitude spots and Smalls light as well, as he described it. Latitude 51 43' was first used, as it was known to be the nearest to the ship's place, then 51 33', and last 51 53', all worked with the same chronometer time. The first one plots 15' East of the position by dead reckoning. The longitudes are not quite 27 miles apart as described, but 25 and 25.7, respectively. The latitude by dead reckoning increased 8 miles intersects the line of position 31' East of the longitude which the incorrect latitude would have given. It will now be shown how to find the sun's true bearing to correspond with the examples just given, by an altitude azimuth. The rule follows on the next page. Sun's declination 23 25' 90 00 Sun's polar distance 113 25 True altitude 11 44 Secant =.00917 Latitude by dead reckoning 51 43 Secant =.20792 Divided by 2)176 52 Half sum 88 26 Cosine = 8.43680 Polar distance-113 25 Remainder 24 59 Cosine = 9.95733 Su...
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