Artículos relacionados a Statistics by algebraic and graphic methods; intended...
Statistics by algebraic and graphic methods; intended primarily for students of engineering and architecture - Tapa blanda
Sinopsis
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1908 Excerpt: ...after passing cd to a negative maximum under de, when it negatively decreases rapidly again to zero under ea. The negative maximum is found to be numerically slightly larger than the positive maximum, and the dangerous section of the beam, so far as flexure is concerned, is under de. Observe that the sections where the flexure reaches its greatest values, whether positive or negative, are those in which the shear passes through zero--a phenomenon of inevitable occurrence, as will be shown in the next section. Exercise 19. A horizontal beam of 30 ft. span, supported at each end, carries loads of 90c, 600, 1800, and 1200 lbs. at points 6, io, 18, and 25 ft. respectively from the left end. Neglecting the veight of the beam itself, determine by both methods the numerical value of the flexure at sections 8, 12, 18, and 30 ft. from the left end. Record results side by side for comparison. Suggestions. Take the scale of lengths as great as 1 in. = 4 ft. Take some convenient round number for the magnitude of H. See PI. IX for a solution. 71. Connection Between Shear and Change in Flexure.--It will be useful to see if there is a simple relation between the flexure at the end of an interval and the shear and flexure at the beginning of the interval. Accordingly, let A C, Fig. 26, p be any segment of a beam, Cx and _r,-' Sjj Ca, and and j&fathe ends of the F-a 1 "-jt:'?_C';?.C interval and values of the flexures Fig. 26. existing there respectively, Px the resultant of all the forces at the left of Cv P2 of those in the interval CxC2. Dimensions as shown. Then M2 = Px (ax + a2 + a3) + P2a3 and Mx = Pxax. Subtracting the latter from the former, M3-Mx = Px (a2 + as) + P,a%. But Px is the measure of the shear at the beginning of the interval and (a2--a3) is the ...
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Reseña del editor
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1908 Excerpt: ...after passing cd to a negative maximum under de, when it negatively decreases rapidly again to zero under ea. The negative maximum is found to be numerically slightly larger than the positive maximum, and the dangerous section of the beam, so far as flexure is concerned, is under de. Observe that the sections where the flexure reaches its greatest values, whether positive or negative, are those in which the shear passes through zero--a phenomenon of inevitable occurrence, as will be shown in the next section. Exercise 19. A horizontal beam of 30 ft. span, supported at each end, carries loads of 90c, 600, 1800, and 1200 lbs. at points 6, io, 18, and 25 ft. respectively from the left end. Neglecting the veight of the beam itself, determine by both methods the numerical value of the flexure at sections 8, 12, 18, and 30 ft. from the left end. Record results side by side for comparison. Suggestions. Take the scale of lengths as great as 1 in. = 4 ft. Take some convenient round number for the magnitude of H. See PI. IX for a solution. 71. Connection Between Shear and Change in Flexure.--It will be useful to see if there is a simple relation between the flexure at the end of an interval and the shear and flexure at the beginning of the interval. Accordingly, let A C, Fig. 26, p be any segment of a beam, Cx and _r,-' Sjj Ca, and and j&fathe ends of the F-a 1 "-jt:'?_C';?.C interval and values of the flexures Fig. 26. existing there respectively, Px the resultant of all the forces at the left of Cv P2 of those in the interval CxC2. Dimensions as shown. Then M2 = Px (ax + a2 + a3) + P2a3 and Mx = Pxax. Subtracting the latter from the former, M3-Mx = Px (a2 + as) + P,a%. But Px is the measure of the shear at the beginning of the interval and (a2--a3) is the ...
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