An inductive arithmetic for intermediate and higher grades of public and private schools - Tapa blanda

Dunbar, Joseph Henry

 
9781130505412: An inductive arithmetic for intermediate and higher grades of public and private schools

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Sinopsis

This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1902 Excerpt: ...or 10 times 210, or 2160, cubic feet. We next find the volume of the pyramid that must be added to the frustrum to form the complete pyramid. The altitude is evidently 30 less 10, or 20, feet, and the volume is % of 20 times 12 times 8, or 4 times 160, or 04-0, cubic feet. The volume of the complete pyramid being 2160 cubic feet, and the volume of the added pyramid 640 cubic feet, the volume of the frustrum is 2160 less 640, or 1520, cubic feet. Ex. 2. While the producing surface of the frustrum has moved perpendicularly to itself through 21 feet, its diameter has lost 14 feet, or JJ, or-£%, of its original length. Therefore, had the producing surface continued its motion until reduced to a point it would have passed through if of 21 feet, or 36 feet. We next find the volume of the complete imaginary cone. This volume is % of 36 times 24 times 24 times.7854, or 12 times 3 times 8 times 3 times 8, or 12 times 9 times 8 times 8, times.7854, or 5428.6848, cubic feet. The altitude of the imaginary added cone is 36 less 21, or 15, feet, and its volume is 15 times 10 times 10 times.7854, or 15 times 100 times.7854, or 1178.10, cubic feet. The volume of the frustrum, therefore, is 5428.6848--1178.10, or 4250.5848 cubic feet. NOTE. Observe the four following distinct processes in the preceding solutions. (i) To find the altitude of the complete pyramid or cone. ( 2) To find the volume of this pyramid or cone. 13 ) To find the volume of the added pyramid or cone. (4) To find the volume of the frustrum. Ex. 104. 1. A circle whose diameter is 3 feet moves perpendicularly to itself, and constantly and regularly diminishes until its diameter is reduced to 1 ft. 8 in. The perpendicular distance between its original and its final position is 3 ft. 6 in. What is the v...

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Reseña del editor

This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1902 Excerpt: ...or 10 times 210, or 2160, cubic feet. We next find the volume of the pyramid that must be added to the frustrum to form the complete pyramid. The altitude is evidently 30 less 10, or 20, feet, and the volume is % of 20 times 12 times 8, or 4 times 160, or 04-0, cubic feet. The volume of the complete pyramid being 2160 cubic feet, and the volume of the added pyramid 640 cubic feet, the volume of the frustrum is 2160 less 640, or 1520, cubic feet. Ex. 2. While the producing surface of the frustrum has moved perpendicularly to itself through 21 feet, its diameter has lost 14 feet, or JJ, or-£%, of its original length. Therefore, had the producing surface continued its motion until reduced to a point it would have passed through if of 21 feet, or 36 feet. We next find the volume of the complete imaginary cone. This volume is % of 36 times 24 times 24 times.7854, or 12 times 3 times 8 times 3 times 8, or 12 times 9 times 8 times 8, times.7854, or 5428.6848, cubic feet. The altitude of the imaginary added cone is 36 less 21, or 15, feet, and its volume is 15 times 10 times 10 times.7854, or 15 times 100 times.7854, or 1178.10, cubic feet. The volume of the frustrum, therefore, is 5428.6848--1178.10, or 4250.5848 cubic feet. NOTE. Observe the four following distinct processes in the preceding solutions. (i) To find the altitude of the complete pyramid or cone. ( 2) To find the volume of this pyramid or cone. 13 ) To find the volume of the added pyramid or cone. (4) To find the volume of the frustrum. Ex. 104. 1. A circle whose diameter is 3 feet moves perpendicularly to itself, and constantly and regularly diminishes until its diameter is reduced to 1 ft. 8 in. The perpendicular distance between its original and its final position is 3 ft. 6 in. What is the v...

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