Arithmetic, rational and practical; Wherein the properties of numbers are clearly pointed out, the theory of the science deduced from first ... explained, and the whole reduced to Volume 1 - Tapa blanda
Sinopsis
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1772 edition. Excerpt: ...product, adding 2, the Total rem. 11 Divide 2061 2 by 56. Here the component parts of (;he divisor are 7 x 8; and as 4 in the first division happens to be the last and only remainder, there is no prior divisor into which it can be multi« plied; so this 4 is the total remainder, 7) 20612 Rem. 8) 2944 4 368 Tot. rem. 4 Complete?. quotient. 3 0 56 EXAMPLE V, Divide 7842 by 42. Here the component parts of the 6)7842 divisor are 6x7; and as 5, the on---ly remainder, is in the last division, 7)1 307 the total remainder is found by----multiplying it into the preceding 186 divisor 6, and so the fraction is f §. Tot. rem. Or rather, when the only remainder happens in the last division, make quotient it the numerator, and the last di-or, visor the denominator; and so the fraction here will be j-, which is equal in value to f§; as will appear in the doctrine of vulgar fractions. If the given divisor consist of any figure repeated, as 222 333 444 5555 &c the component parts may be in x 2, in x 3, m x 4, &fc. EXAMPLE VI, Divide 78943 by 444, Here 4) 111)78943(711 Rem. 177 3 Total rem. 355 Complete? 355 quotient 1 'f Jijere the component parts of the divisor are 111 x 4; and 777 the total remainder is--made up as formerly, 124 viz. 3 x 1 11 =333, in 333 + 22 = 355. 133 111 Rem. 22 5. In division the operation may frequently be rendered more simple, if you divide both divisor and dividend by any number, or numbers, that will divide both without any remainder; and when by this method you can bring them no lower, divide the remaining dividend by the remaining divisor. P L E I. EXAM Divide 1692 by 468. Here I divide 1692 both divisor and di-vidend twice by 2, 468 I 234 1 17 39 and again twice by 3; and as I cannot proceed in this manner any...
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Reseña del editor
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1772 edition. Excerpt: ...product, adding 2, the Total rem. 11 Divide 2061 2 by 56. Here the component parts of (;he divisor are 7 x 8; and as 4 in the first division happens to be the last and only remainder, there is no prior divisor into which it can be multi« plied; so this 4 is the total remainder, 7) 20612 Rem. 8) 2944 4 368 Tot. rem. 4 Complete?. quotient. 3 0 56 EXAMPLE V, Divide 7842 by 42. Here the component parts of the 6)7842 divisor are 6x7; and as 5, the on---ly remainder, is in the last division, 7)1 307 the total remainder is found by----multiplying it into the preceding 186 divisor 6, and so the fraction is f §. Tot. rem. Or rather, when the only remainder happens in the last division, make quotient it the numerator, and the last di-or, visor the denominator; and so the fraction here will be j-, which is equal in value to f§; as will appear in the doctrine of vulgar fractions. If the given divisor consist of any figure repeated, as 222 333 444 5555 &c the component parts may be in x 2, in x 3, m x 4, &fc. EXAMPLE VI, Divide 78943 by 444, Here 4) 111)78943(711 Rem. 177 3 Total rem. 355 Complete? 355 quotient 1 'f Jijere the component parts of the divisor are 111 x 4; and 777 the total remainder is--made up as formerly, 124 viz. 3 x 1 11 =333, in 333 + 22 = 355. 133 111 Rem. 22 5. In division the operation may frequently be rendered more simple, if you divide both divisor and dividend by any number, or numbers, that will divide both without any remainder; and when by this method you can bring them no lower, divide the remaining dividend by the remaining divisor. P L E I. EXAM Divide 1692 by 468. Here I divide 1692 both divisor and di-vidend twice by 2, 468 I 234 1 17 39 and again twice by 3; and as I cannot proceed in this manner any...
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